/* Compute a table of cubes. */

#include  <stdio.h>

#define  N  15
#define  MAX  3.5

int main()
{
   int i;
   double x, cube();
    
   printf("\n\nINTEGERS\n");
   for (i = 1; i <= N; ++i)
      printf("cube(%d) = %d\n", i, cube(i));
   printf("\n\nREALS\n");
   for (x = 1; x <= MAX; x += 0.3)
      printf("cube(%f) = %f\n", x, cube(x));
}

double cube(x)
double  x;
{
   return (x * x * x);
}

It gives the wrong answers for the integer arguments, and it does so because integer arguments are passed as if their bit representation were double. It is unacceptable as C++ code.
Instructions
Re-code this program as a C++ program that uses a proper function prototype. Test your program by compiling it using a C++ compiler. C++ compilers enforce type compatibility on function argument values. Therefore, the integer values are properly promoted to double values.
Paste the source code of your program below and click the OK, I'm Done button when you are ready to submit this exercise.